C(x)=3x^2+x+500

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Solution for C(x)=3x^2+x+500 equation:



(C)=3C^2+C+500
We move all terms to the left:
(C)-(3C^2+C+500)=0
We get rid of parentheses
-3C^2+C-C-500=0
We add all the numbers together, and all the variables
-3C^2-500=0
a = -3; b = 0; c = -500;
Δ = b2-4ac
Δ = 02-4·(-3)·(-500)
Δ = -6000
Delta is less than zero, so there is no solution for the equation

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